1.6t^2-32t-50=0

Solution for 1.6t^2-32t-50=0 equation:

1.6t^2-32t-50=0

a = 1.6; b = -32; c = -50;
Δ = b2-4ac
Δ = -322-4·1.6·(-50)
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8\sqrt{21}}{2*1.6}=\frac{32-8\sqrt{21}}{3.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8\sqrt{21}}{2*1.6}=\frac{32+8\sqrt{21}}{3.2}
$